Question

How do you find the remainder of:
(x^5-4x^4+x^3-7x+2)/(x+3)

Answer 1

to state the obvious; by dividing it out

Answer 2

division is division regardless .....


x^4 -7x^3 +22x^2 -66x +191
------------------------
x+3 | x^5 -4x^4 +x^3 -7x +2
-(x^5 +3x^4)
------------
-7x^4 +x^3
-(-7x^4 -21x^3)
------------------
22x^3 -7x
-(22x^3+66x^2)
---------------
-66x^2 -7x +2
-(-66x^2 -198x)
-----------------
191x + 2
-(191x +573)
--------------
-571 <-- remainder

Answer 3

if i kept track of it that is

Answer 4

put whats left back over the (x+3)

Answer 5

one trick to keep things straight would be simply to negate (x+3) to begin with: -x-3 and that way you aint gotta worry about the subtraction per se