Question

Factor: x^6-64

Answer 1

\[x^2-y^2=(x+y)(x-y)\]
so,
\[(x^3)^2-(8)^2=(x^3-8)(x^3+8)\]
\[x^3-y^3=(x-y) (x^2+x y+y^2)\]
and
\[x^3+y^3=(x+y) (x^2-x y+y^2)\]
so,

Answer 2

\[[(x)^3-(2)^3]+[(x)^3+(2)^3]=(x-2)(x^2+2x+4)(x+2)(x^2-2x+4)\]