Question

ok, I should be done, but I'm not, my code has passed all of the tests, the problem here is how display_hand displays one character per line. Also choosing to play more than once per hand is giving me issues, but I'll figure that out on my own I think.

NOTE: I am using python 3, hence the input() vs raw_input() and the print() as a function.

here's my code http://paste.org/pastebin/view/38082

any ideas are more than welcome

Answer 1

erm, that question is for PS 5

Answer 2

try using

print(letter, end='') #those are two single quotes with nothing enclosed after end =

in line 108 (in that link you posted).

Answer 3

when a function returns a boolean (True or False) you can use it in a conditional statement without a comparison - in line 239, "is True' isn't necessary: you can (some would say should) just use
"if is_valid_word(word, hand, word_list):"

i think you have another problem: is_valid_word is modifying the hand that is passed to it: http://pastebin.com/hHcLTkmi

Answer 4

Excellent point bwCA. jesse.bo, mutable objects like lists and dictionaries get passed by reference in Python. For us, that means that it is possible to modify these objects within a function and affect the original. So, we have this example:
http://codepad.org/TvCbr2QH

def ref_no_change(myDict):
tempDict = myDict.copy() # we create a new object for a mutable object copy
tempDict['a']=0

def ref_change(myDict):
tempDict = myDict # we do not create a new object for a mutable object assignment
myDict['a']=0

aDict = {'a':1}
print('Dictionary before functions:',aDict['a']) # returns 1
ref_no_change(aDict)
print('Dictionary after ref_no_change:',aDict['a']) # returns 1
ref_change(aDict)
print('Dictionary after ref_change:',aDict['a']) # returns 0, oh noes!