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Mathematics
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8x5 _____ 4x3 Divide the Monomials! The 5 and 3 are little
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\[\frac{8^5}{4^3}?\]
But with an X between both
8x5 4x3
\[\frac{8x^5}{4x^3}\]
Yes
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\[\frac{8x^5}{4x^3}=\frac{4*2*x*x*x*x*x}{4*x*x*x}\]
(8/4)(x^(5-3)) = 2 * x^2
2x^2
when u cancel what cancels u get 2x^2 like they put
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