how close to -3 do we have to take x for the inequality 1/(x+3)^2 700
-within at least 0.097
-within at least 0.057
-within at least 0.037
-within at least 0.077
-within at least 0.017

Question

how close to -3 do we have to take x for the inequality 1/(x+3)^2 >700
-within at least 0.097
-within at least 0.057
-within at least 0.037
-within at least 0.077
-within at least 0.017

amistre64 · Answer

1/(x+3)^2 >700-.097

amistre64 · Answer

1/(700 - (error)) = (x+3)^2

x = $-3\pm\sqrt{\cfrac{1}{700-(error)}}$

josee · Answer

its not .097

amistre64 · Answer

hmm .... we might have to just tack it on the end then :)

amistre64 · Answer

$$-3\pm\sqrt{\cfrac{1}{700}}\pm(error)$$
maybe?

josee · Answer

what do you put in for error?

amistre64 · Answer

its just a guess, but id say the given requirements: -within at least 0.097

-within at least 0.057
-within at least 0.037
-within at least 0.077
-within at least 0.017