In how many ways can 9 instructors be assigned to six sections of a course in mathematics?

Question

anonymous · Answer

9 x 6 = 54 ways

anonymous · Answer

$$\left(\begin{matrix}9 \ 6\end{matrix}\right)$$ = 84

anonymous · Answer

I don't know if this is right I think that i have to go 9*8*7*6*5*4*3*2*1=362880 It's probability so i have no idea

amistre64 · Answer

9.8.7.6.5.4

anonymous · Answer

$$_{9}P_{6}=9!/(9-6)!=9*8*7*6*5*4$$
Basically this is a permutation.  Pretending that the classrooms are boxes that we are holding still, we have 9 professors, so the question is how many different ways can we order the professors (equivalent to sticking them in each of the classrooms) taking them six at a time?