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The expression (3^4x)^(7x) can be written as 3^f(x) where f(x) is a function of x. Find f(x) =
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f(x0=28x^2
why 28x^2 and not just 28x?
\[ (x^{a})^{a}= x^{a.a}=x^{a^{2}}\]
so we multiply both exponents to form the new exponent
oh 4x*7x is 28x^2. forgot the other x. Okay thank you
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