Solve the system of equation algebraically
(x+2)^2+(y-16)^2=1
y=-4x+8
i have part of it done, i just dont know how to use the quadratic formula to find the rest of it

Question

Solve the system of equation algebraically
(x+2)^2+(y-16)^2=1
y=-4x+8
i have part of it done, i just dont know how to use the quadratic formula to find the rest of it

anonymous · Answer

In this i foiled the first set, and after pluging in -4x+8 as y, i foiled the second part of the first set. it comes to be 17x^2+68x+67=0. I dont know what to do after that.

mimi_x3 · Answer

Well, im not sure though
but if you want to use the quadratic formula for 17x^2 + 68x+67 , then a = 17 , b=68, c= 67 then substitute it to the quadratic formula. Not sure if I'm right though

anonymous · Answer

after pluging it into the formula, i get {-1.76 and -2.24}, so are these x or y?

mimi_x3 · Answer

http://www.wolframalpha.com/input/?i=%28x%2B2%29^2%2B%28y-16%29^2%3D1%2C+y%3D-4x%2B8