Question

We just started Logarithms.
2^(2x+1) - 3*2^(x) +1 = 0
Thanks!

Answer 1

5log(c^2-7)-8log(c^-1-2)

Answer 2

uhh, care to show working out?

Answer 3

should i put the i simplify that ir should i find the aproximate value??

Answer 4

i want to show but im lazy using the equation..

Answer 5

I can put the equation into my calculator as well, he wants working out.

Answer 6

uhh, care to show working out?

Answer 7

Can I just do this
(2x+1) log 2 - 3*x log 2 +1 =0

Answer 8

\[2^{2x+1}-3\cdot 2^x+1=0\]
\[2\cdot 2^{2x}-3\cdot 2^x+1=0\]
\[(2^x-1)\cdot(2\cdot 2^x-1)=0\]
\[2^x=1\quad\vee\quad 2^x=1/2\]
\[x=0\quad\vee\quad x=-1\]