Question

how to you solve 16^x - 5 * 8^x = 0
using logarithms?

Answer 1

please show working out, thanx :)

Answer 2

\[16^x-5\cdot 8^x=0\]
\[2^{4x}-5\cdot 2^{3x}=0\]
\[2^{3x}\cdot (2^{x}-5)=0\]
\[2^{x}=5\]
\[x=\log_{2}5\]