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Mathematics 9 Online
OpenStudy (anonymous):

x^2 – 16x + 15 = 0

OpenStudy (anonymous):

x^2-15x-1x+15 x(x-15)-1(x-15) (x-1)(x-15)

OpenStudy (anonymous):

(x-15)(x-1)=0 --> (x-15) =0 or (x-1) =0 -->x=15 or x=1

OpenStudy (anonymous):

since (x-1)(x-15) = 0 x=1 or x=15

OpenStudy (anonymous):

so are they positive or negative

OpenStudy (anonymous):

positive

OpenStudy (anonymous):

Factor: (x-15)(x-1)=0 Set both 'factored parts' equal to 0; x=15 and x=1

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