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Mathematics 18 Online
OpenStudy (anonymous):

((x^2+1)(x-1)/(x^2-1) = (x^2+1)/(x+1) why is the denominator of the answer become (x+1)?

OpenStudy (anonymous):

\[(x^2+1)(x-1)/(x^2-1)\]\[(x^2+1)(x-1)/(x-1)(x+1)\]\[(x^2+1)/(x+1)\]

OpenStudy (anonymous):

The identity goes:\[a^2-b^2=(a-b)(a+b)\]

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