Question

GIVE EXACT AND APPROXIMATE SOLUTIONS TO THREE DECIMAL PLACES

(x+6)^2=16

Answer 1

Take the square root of both sides to get \[x+6=\left(\begin{matrix}+ \\ -\end{matrix}\right)4\]

Then subtract 6 from both sides.

Answer 2

(x+6)^2 = 16 --> x^2 + 12x + 36 = 16 --> x^2 + 12x + 20 = 0 --> (x+10)(x+2) = 0 --> x=-10, x=-2 ... --> is this the ans?

Answer 3

oh maybe not...

Answer 4

I think it is supposed to be in decimal form

Answer 5

that is what has me lost

Answer 6

Well both answers to this (-2 and -10) are integers, not decimals. So if you HAVE to give three decimal places, it would be -2.000 and -10.000