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factor: 2x(a+b)-3z(a+b)
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(2x-3z)(a+b)
thanks!
do you know how do you factor a^2-ac+ab-bc
by grouping?! you have a nice common factor of \[a+b\]
you can solve that one like sat said, by grouping: (a^2-ac)+(ab-bc) a(a-c)+b(a-c) (a+b)(a-c)
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