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Mathematics 23 Online
OpenStudy (anonymous):

factor: 2x(a+b)-3z(a+b)

OpenStudy (anonymous):

(2x-3z)(a+b)

OpenStudy (anonymous):

thanks!

OpenStudy (anonymous):

do you know how do you factor a^2-ac+ab-bc

OpenStudy (anonymous):

by grouping?! you have a nice common factor of \[a+b\]

OpenStudy (anonymous):

you can solve that one like sat said, by grouping: (a^2-ac)+(ab-bc) a(a-c)+b(a-c) (a+b)(a-c)

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