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can someone help me solve for x. 3x^2=-7x-2
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Do you know Bhaskara?
no.
x = -1/3
\[ x =- \frac{1}{3} \]
had lunch with him yesterday
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there should be 2 solutions.
x = -2
thank you!!!
\[ x =- \frac{1}{3} \] x = -2
sorry had a brain fart :-D
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* Bhaskara: x = ( -b(+-)√(b^2-4ac) )/2a * Your equation: 3x^2 + 7x + 2 = 0 * a = 3; b = 7; c = 2 * x = ( -7 (+-) √(7^2-4*3*2) ) / 2*3 * x = (-7 (+-) √25) ) / 6 * x = (-7 (+-) 5 ) / 6 * x1 = (-7+5)/6 = -1/3 * x2 = (-7-5)/6 = -2
oh Ive only heard it called the quadratic formula.
I like hear more about people than formulas! ;)
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