Question

plzzzzzzzz helpppppppp!!!
3+sqrt{z-9}=sqrt{z+6}

Answer 1

square both sides to get
\[3+\sqrt{z-9}=\sqrt{z+6}\]
\[3^2+2*3*\sqrt{z-9}+z-9=z+6\]
\[6*\sqrt{z-9}+z=z+6\]
\[6*\sqrt{z-9}=6\]
\[\sqrt{z-9}=1\]
\[z-9=1 so z=10\]

Answer 2

so z= 10