Question

prove that f(x) = sqrt(x) is continous at x= 4

Answer 1

lim as x approaches 4 from the negative side =2
lim as x approaches 4 from the positive side =2
f(4)=2
thus the function has no break at the point x=4 because from each side it approaches to one value, and the function at x=4 is the same value.