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explain how to factor 6ab-8bc-4bd?
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try look for the commons.
what i can see is only 2 is common here, as it goes with 6, 8 and 4. all three.
so, 2(ab-4bc-2db)
2(ab-4bc-2db) Now you can also be b is also common from all these three. so, 2b(a - c - d)
thanks!
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welks.
how can you take a common?? there is no a on the second and third term?
6ab-8bc-4bd? 2(3ab-4bc-2db) 2b(3a - 4c - 2d)
Here you go, idk why those numbers didn't appeared.
that's same as mine! xD
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Lol Looks same to me
Right.
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