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the sum of the digits of a two digit number is 7. When the digits are reversed , the number is increased by27. Find the original number..
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solve: a+b=7 10a+b=27+10b+a
10a+b=27+10b+a 9a=27+9b a=3+b a+b=7 a=7-b a=3+b 7-b=3+b 2b=10 b=5 a=7-b a=7-5 a=2 So the numbers are: 10a+b=20+5=25 a+10b=2+50=52 The original number is 25
I agree with fiddlearound
Do you understand what he did??
i'll try
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