Question

simplify with positive exponents (3x^2y^3)/(12x^-1y^-6)^2

Answer 1

\[3x ^{2y ^{3}}=(3x ^{y ^{3}})^{2}\]
\[[(12x ^{-1y ^{-6}})^{2}=144*\left[ (x ^{y ^{-6}})^{-1} \right]^{2}\]
Results=\[(x ^{y ^{3}+y ^{-6}})^{2}/16\]