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what is this question asking for: Determine all real values t and s (1-s,3)=(7,t2)?
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Well, on the face of it, s = -6 and t= sqrt(3).
\[(1-s,3)=(7,t^2)\] \[1-s=7\]\[3=t^2\] \[s=-6\]\[t=\sqrt{3}\]
wait, sorry, it's t-2. *facepalm*
In this case \[t-2=3\]\[t=5\]
Thank you so very much, it is greatly appreciated
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