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if cot(B)=3 and cot=cos/sin. then is cos=3 and sin=1?
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yup
okay i did something wrong though
yes?
tan=1/3 but i got sin, cos, sec, csc wrong
i said sin=1, cos=3, sec=1/3 and csc=1
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sec B= 1/cosB = 1/3 csc B = 1/ sin B = 1/1 = 1
if cot(B)=3/1 then we have the oppsite side of B is 1 and the adjacent side to B is 3 heres a triangle |dw:1315509617873:dw|
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