Question

evaluate this indefinite integral
int (3x-2)^(20) dx...i got up to u=3x-2 and du=3

Answer 1

you are on the right track

Answer 2

yes but where do i go from here

Answer 3

suppose u=3x-2
du=3dx
1/3*u^20du
u^21 /63

Answer 4

(3x.2)^21/63

Answer 5

add one to the exponent then divide then sub you back in don't forget to add a C for a constant

Answer 6

o ok cool thanks