Question

Find the following quotient:
x^2-4
-------
x+2

Answer 1

= (x+2)(x-2) / (x+2) = x-2

Answer 2

\[x^2-y^2=(x+y)(x-y)\]
\[\frac{(x)^2-(2)^2}{x+2}\]
\[=\frac{\cancel{(x+2)}(x-2)}{\cancel{(x+2)}}\]
\[=x-2\]