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what is the square root of negative two over 9
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\[\sqrt{\frac{-2}{9}}\] \[\sqrt{\frac{-1*2}{3*3}}\] \[\sqrt{-1}=i\] \[\frac{i}{3}\sqrt{2}\]
three square roots of 2 over 9
or just square roots of two over 3
well the negative is in the outside like this i will draw it:
iam sorry i reas it wrong it looks like this i will draw it.
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lolz
lololol!! |dw:1315530607078:dw|
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