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6x^3 + 31x^2 + 5x
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x(x+5)(6x+1)
Here we can factor out x outside because "x" is the common factor among them 6x^3 + 31 x^2 + 5x = x ( 6x^2 + 31 x +5 ) Then we can apply the grouping method to factor it out further : x [ 6x^2 + 30x + 1x + 5 ] = x [ 6x(x +5) +1 (x +5 )] = x ( 6x +1 ) ( x + 5 ) This is the final answer:)
thank you both so much! one question..why is there an X on the outside of the parenthesis?
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