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find the values of x if f(x)=g(x) f(x)=x to the fourth - 2x to the 2nd g(x)= 2x to the 2nd please explain!!
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set \[x^4-2x^2=2x^2\]and solve for x
start with \[x^4-4x^2=0\] \[x^2(x^2-4)=0\] \[x^2(x+2)(x-2)=0\] \[x=0,x=-2,x=2\]
so you factor it twice? and its the opposite of the the 2s in the parenthesis?
yes factor all the way down
then set each factor = 0 and solve
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ok thanks that helped a lot!
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