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2z^2 - 3 = -5z
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come on man, just add 5z to both sides
2z^2+5z-3=0
then do i factor or use the formula
either or. both will get u the same answer
then how do i factor it
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because it's easier
(2x+a)(x+b) a*b=-3 2b+a=5 solve for a and b
in this case its probably easier to use the quadratic formula, (-b±√b^2-4ac)/2a = (-5±√25-24)/4 = -5+1 / 4 and -5 - 1 / 4 thus roots are z=-1 and z = -3/2
cool thanks
that makes alot more sense
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i actually would have preferred to factor. (2x-1)(x+3)=2x^2+5x-3 x=1/2 and x=-3 also it should b sqrt(25+24)
what do you mean it should be sqrt does that mean the answer is wrong
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