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Find average value f(theta)= sec^2(theata/2), [0/pi]
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\[sec^2(\theta/2)\]
\[\frac{1}{\pi -0}\int_0^{\pi } \text{Sec}^2\left(\frac{x}{2}\right) \, dx\]
you need help integrating that?
would it be\[1/\Pi\] ?
The integral doesn't converge http://www.wolframalpha.com/input/?i=Integrate%5BSec^2%5Bx%2F2%5D%2C {x%2C0%2CPi}%5D
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