Question

Find the equation of the line through the point (12,15) that is parallel to 8x+3y= 8

Answer 1

8x+3y=8
8x=-3y+8
x=(-3/8)y+1
Hence its slop is -3/8, and thus, so its the slope of your line, since they're parallel.
So equation of line is y=(-3/8)x+c
But we know also that it passes through (12,15).
Thus 15=(-3/8)(12)+c
15 = -4.5+c
c=15+4.5 = 19.5 = 39/2
Hence equation of line is y=(-3/8)x+39/2
8y = -3x+156
8y+3x=156

Answer 2

so the answer is y=(-3/8)x+39/2)