Question

anyone know about roots? last section for my review study...see attached...number 143

Answer 1

i know

Answer 2

check out attachment

Answer 3

the roots are when you substitute the value to the x it will satisfy the equation

Answer 4

x^2-x-1=0

x^2-x=1

x^2-x+1/4=1+1/4

(x-1/2)^2=5/4

x-1/2=sqrt(5)/sqrt(4)

x=[sqrt(5)/sqrt(4)]-1/2

Answer 5

\[x^2+x-4=0\]\[Δ=b^2-4ac=1^2-4(-4)=17\]\[x_{1,2}=\frac{-b \pm \sqrt{Δ}}{2a}=\frac{-1\pm \sqrt{17}}{2\times1}\]\[x_{1,2}=\frac{-1\pm \sqrt{17}}{2}\]