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OpenStudy (anonymous):
The following system is solved by substitution. Which expression is substituted for z in the second and third equations? x + 5y – z = 6 3x – y – 2z = 4 3x – 2y + 3z = 13
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OpenStudy (chaise):
x+5y-z=6 If we rearrange this to make z the subject we can substitute this into the last two equations. x+5y-6=z z=x+5y-6
OpenStudy (anonymous):
Why thank you again :) lol
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