Question

the perimeter of a triangle is 47 centimeters. The longest side is 7 centimeters less than the sum of the other two sides. Twice the shortest side is 4 centimeters less than the longest side. Find the lengths of all sides.

Answer 1

let the longest side be x,shortest side be z and the other side be y
x+y+z=47
x=(y+z)-7
x=2z+4

now solve for x y and z

Answer 2

a+b+c = 47cm
let a be the longest side now
a=b+c-7
shortest side be c
2c = a-4
c=(a-4)/2
a=b+c-7
a=b+(a-4)/2
(2a-a+4)/2 =b
(a+4)/2=b
a+b+(a-4)/2 = 47 cm
(2a+2b+a-4) = 94cm
(3a+2b-4)= 94cm
solve further i think i did wrong some where have some work tell u later