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88 rounded to the nearest tenth
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0.9
|dw:1315580806281:dw|
thats what the prob looks like
16^2-11^2=x^2
leace medal if it helped
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a For the following find teh side length x . Round your answer oto the nearest tenth
256-121
sqrt 135=x
11.6
find x by pythagoras \[16^2=x^2+11^2\] \[x^2=135\]\[x=\sqrt{135}\]\[x=11.618\]\[x=11.6\]
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thanu ummmm soo 11.6 is the final answer what would it be rounded to the nearest tenth??
yes
11.6 is the final answer
thnks
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