Question

the perimeter of a triangle is 47 centimeters. The longest side is 7 centimeters less than the sum of the other two sides. Twice the shortest side is 4 centimeters less than the longest side. Find the lengths of all sides.

Answer 1

Why u post it again?

Answer 2

bc i dont understand still how you got the answer

Answer 3

i do not understand your explanation

Answer 4

Sides, x , y and x+y-7 add up to 47...that the bit u didn't understand?

Answer 5

let shortest = x, longest = y, the thrid side = z
y=x+z-7 (longest side is 7 cm less than sum of x and z)
2x + 4 = y (twice the shortest is 4 cm less than longest)
the perimeter is 47, so
x + y + z = 47

you now have system of equations
3 equations and 3 unknowns...can u take it from there?

Answer 6

the equations
x+y+z = 47
x+z-7 = y
2x+ 4 = y

Answer 7

do you want me to solve the whole thing?

Answer 8

I already did it, he didn't get it...

Answer 9

2x+2y-7=47
2x+4 = x+y-7 -> x= y-11 etc... (ie sub in first one)

Answer 10

im trying to understand it . i am having a hard time. i dont want someone to give me the answer i need to undetstand it for myself

Answer 11

ok but do you understand how i set up the problem? with the system of equations
i would like to know what you dont understand so i can help you more, are you not familiar with how to solve system of equations? or you just have hard time set the problem up?

Answer 12

I got it. thanks for helping