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Mathematics 7 Online
OpenStudy (anonymous):

How would I determine the integral of (1/(xsquared))dx

OpenStudy (anonymous):

x^-2 then add one to the exponent and divide

OpenStudy (anonymous):

you should write\[ 1/x^2 \] as \[x^-2\] and then calculate using the standard Integral x^n formula answer is - \[-1/x\]

OpenStudy (anonymous):

And don't forget the constant....:-)

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