FFactor the trinomial. r^2 - 2rd - 80d^2
Hewweo.
Hey!
\[r-80 d^2 \]
LOL...that is the same answer I came up with, but it says it's not correct.
Um... is somebody plugging the values straight into wolfram?
there's no doubt in that. :P
Yes and the "input" is not coming out right so therefore, it is giving the wrong answer.
haha: \[(r - d)^2 - 81d^2\]
That's the best I can do..
Let me check...
No, that's not right either. hmmmm
hey mathsboy how did you come oup with the eq'n in my question
It says to rewrite the trinomial in descending powers of r, if necessary. First, factor out any common factors then use the FOIL method in reverse. To do this, factor the first and last terms of the trinomial. Use numbers that, when added together, result in the middle term of the trinomial.
might be there is some mistake in mathlab.
Yea, could be. I think I will ask for a replacement question.
Nope, it's most likely the interpretation of the copy/pasted text.
Yea, that may be true too. It does not seem to be interpreting what I am typing in correctly.
we cannot paste text in mathlab.
When I type it into Wolfram, it is interpreting it as r^2/2 - 80d^2
\[(r-10 d) (r+8 d) \]
Answer^
Correct answer is (r+8d)(r-10d)
I gave it to you! :O
LOL, I know and I got impatient so now I have to do an alternate question. haha
LOL.
okay, try this one. s^2 - 8sz - 20z^2
(s-10 z) (s+2 z)
btw, how many hours are left for your assignmnt?
This is due tonight. The "other" one isn't due until Sunday.
how many hours are left?
the thing is, it's 02:55am here. I gotta sleep now!! Bye! :) i might be back in 6 hours!!
Okay!!! I totally understand. I just might still be here. LOL Thank you!!
9 hours
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