Question

need help solving: 8x^2=9x using quadric formula

Answer 1

\[\frac{-(-9) \pm \sqrt{(-9)^2 - 4(8)(0)}}{2(8)}\]

Answer 2

Once again my equation editor isn't working - sorry.
Make the equation equal to zero:

8x^2=9x
8x^2-9x + 0 = 0

({-b +/- sqrt{b^2-4ac)/{2a}

a = 8
b = -9
c = 0

Substitute your values in:

x = 9/8
x = 0

Answer 3

Maths boy has kindly substituted in your values :)