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1/4x ^{2}-1/12x-1/6=0 Solve.
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This is a quadratic equation. a = 1/4 b = -1/12 c = -1/6 \[\frac{-b \pm \sqrt{b^2-4ac}}{2a}\] \[x = \frac{-3}{2}\] or \[x=1\]
so you are saying the is x=-3/2&1?
Nope, I am saying x = -3/2 OR x = 1 If you substitute your x value as 1, OR if you substitute your x value as -3/2 you will get your equation equal to zero. When you solve quadratic equations you (pretty much) always get two answers.
ok thanks
If you are unfamiliar with the quadratic formula you should try watching a youtube video on quadratics.
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