Question

1/2x ^{2}-1/4x-1/4=0 solve.

Answer 1

This is a quadratic equation.
a = 1/2
b = 1/4
c = -1/4

\[x=(-b +/- \sqrt{b^2-4ac}/{2a}\]

Substitute in your values.
\[x=-2\]
\[x=1\]

Answer 2

(1/2)(x^2)-(1/4)(x)-1/4=0 Multiply by 4 to eliminate the denominator
2x^2-x-1=0
(2x+1)(x-1)=0
2x+1=0
2x=-1
x=-1/2

x-1=0
x=1

Therefore, x=-1/2 and x=1