Question

Write a quadratic equation having the given numbers as a solution. -4 and -1

Answer 1

(x+4)(x+1)=x^2+5x+4

Answer 2

If it has the solution:
-4 and -1
(x+4)(x+1)=0
Foil it out.
x^2+5x+4

Answer 3

\[(x-(-4))(x-(-1)) = 0\]\[(x+4)(x+1) = 0\]\[x^2 + 5x + 4 = 0\]