Question

Trig

Answer 1

Grit.

Answer 2

lol

Answer 3

Determine the exact value of \[\tan \alpha\]

Answer 4

The disfigured "a" is alpha

Answer 5

\[\tan( \alpha+60) = \frac{40}{8} =5\]\[\tan(\alpha+60)=5\]\[\alpha +60 = \tan^{-1}(5)\]\[\alpha=\tan^{-1}(5) -60\]
find the value of alpha, then
find \[\tan \alpha\]

Answer 6

\[ \tan(\alpha + 60^o ) = 40/8 = 5\]
\[ \alpha + 60^o = \tan^{-1}{(5)}\]
\[ \alpha = \tan^{-1}{(5)} - 60^o\]
\[ \tan(\alpha) = \tan(\tan^{-1}{(5)} - 60^o)\]

Answer 7

The exact answer is ((5-√3))/((1+5√(3) ))