Question

Given the quadratic function f(x) = x^2 – 6x + 9, find a value of x such that f(x) = 25

Answer 1

\[x^2-6x+9=25\]\[x^2-6x-16=0\]
\[(x-8)(x+2)=0\]

Answer 2

x=8 and x=-2

Answer 3

f(x)= x^2 – 6x + 9 = 0 => f(25) = 625 -6(25)+9 = 484

Answer 4

so this is the right answer

Answer 5

raheen f(x)=25
not f(25)

Answer 6

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