Ask
your own question, for FREE!
Mathematics
75 Online
OpenStudy (anonymous):
As a certain object falls, its position s (in meters) above ground after t seconds is given by s(t)=20-5t^2. Whats the average velocity of the object on the interval from t=1 to the time .5 seconds later?? from t=1 to the time .1 seconds later?
Still Need Help?
Join the QuestionCove community and study together with friends!
OpenStudy (anonymous):
Why did you delete your previous post? I almost finished there -.- !! Anyway, the average velocity is equal to the displacement divided by the total time. In this case, the average velocity \(=\frac{s(1.5)-s(1)}{0.5}=\frac{8.75-15}{0.5}=-12.5 m/s\).
OpenStudy (anonymous):
You can similarly do the second part of the problem.
OpenStudy (anonymous):
v(t) = -10t ===> v(1) = -10 , v(1.5) -=10(1.5) = -15 ==> average velocity = [-15 -10]/0.5 = -12.5
OpenStudy (anonymous):
whoops sorry!! :/ thank you though!
OpenStudy (anonymous):
No problem :)
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Juss1Jordan:
The way that this guy treats me make me feel wanted in this world not gonna say his name or @ cs the boy is mines .
31 minutes ago
3 Replies
1 Medal
velmalovesshaggy145:
Isnu00b4t this the opening melody to mood by 24kgoldn feat iann dior? https://voca.
59 minutes ago
7 Replies
2 Medals
Juss1Jordan:
What ever is troubling you , Hurting you , Holding you back, Making you feel bad
2 hours ago
0 Replies
0 Medals