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area of the sector of a circle: r=20,theta:pi/6 radians, a=?
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.5*r^2*theta=100/3*pi
\[Area=\frac{1}{2}\theta r^2\]when theta is measured in radians (as you have it) so\[A=\frac{1}{2} \frac{\pi}{6} 20^2 = \frac{\pi}{12}*400=\frac{100 \pi}{3}\approx104.72\]
[pi/12 ] * 400 = 104.67
r=4, a=47, theta=?
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