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How about LCM's...anyone good at finding those? (3+2v), (9-4v^2), and (3-2v). I this the answer is 9v^2?
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Factor each completely: \[3+2v\text{ and }9-4v^2\text{ and }3-2v\]\[3+2v\text{ and }(3-2v)(3+2v)\text{ and }3-2v\]Write an expression multiplying together all of the common factors, excluding any duplicates that occur between any given pair of expressions:\[(3-2v)(3+2v)\]Which, when distributed, is the same as the second original term. Therefore, the least common multiple is:\[9-4v^2\]
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