Question

4. Factor the following trinomials: x2 + 8x + 15

Answer 1

i think using complete the square is the easiest for this one

Answer 2

\[(x+3)(x+5)\]

Answer 3

since 3(5)=15 and 3+5=8

Answer 4

x^2+8x+15
\[(x^2+8x+16) -1\]
\[(x^2+4x+4x+16)-1\]
\[(x+4)+4(x+4) -1\]
\[(x+4)(x+4) - 1\]
\[(x+4)^2-1\]
\[(x+4-1)(x+4+1) \] since a^2-b^2=(a+b)(a-b)