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OpenStudy (anonymous):
Solve the following trinomial: x2 + 5x + 6 = 0
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OpenStudy (mimi_x3):
(x+3)(x+2) x = - 3 , -2
OpenStudy (anonymous):
(x+2) (x+3) x= -2 and x= -3
OpenStudy (anonymous):
\[x^2+5x+6\] \[x^2+3x+2x+6\] \[x(x+3)+2(x+3)=0\] \[(x+2)(x+3)=0\] either x+2 is 0 or x+3 is 0 \[x+2=0, x=-2\] \[x+3=0 , x=-3\]
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