Question

the perrimeter of a standard- sized rectangular rug is 24 ft. The length is 2 ft longer than the width. find the dimensions

Answer 1

\[2L+2W=24\]
\[L=2+W\]

Answer 2

we shall plug equation 2 into 1
so we have
\[2(2+W)+2W=24 => 4+2W+2W=24=>4+4W=24 => 4W=20 =>W=5\]

Answer 3

\[L=2+5=7\]

Answer 4

This is a simple substitution problem.

2L + 2W == 24

As L == W + 2, rewrite this as

2W + 2(W + 2) == 24

Then,

2W + 2W + 4 == 24
4W + 4 == 24

Answer 5

let width=x ft then length=2+x hence perimeter of rectangle - 2(length+width)=24 =>2(2+x+x)=24
=>2x=10
=>x=5 ft hence length=7ft and width=5 ft