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12x3-8x2=4x factor
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move 4x to the left side. 12x^3-8x^2-4x GCF of all terms is 4x.. so 4x(3x^2 -2x -1) 3x^2 -3x +1x -1 3x(x-1)+1(x-1) 4x(3x+1)(x-1)
Does this make sense?
4x(3x+1)(x+1)?
yes
12x^3-8x^2-4x=0 4x(3x^2-2x-1)=0 4x=0 or (3x^2-2x-1)=0 x=0 or 3x^2 -3x +1x -1=0 x=0 or 3x(x-1)+1(x-1)=0 x=0 or (3x+1)=0 or (x-1)=0 x=0 or x=-1/3 or x=1 so there can be three possible values of x=0,1,-1/3
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